# Thevenin’s Theorem -explanation, equivalent circuit & examples

Circuits can contain many power sources and power dissipation elements. It is common that any one of the elements in the circuit is a variable while all others are fixed. Imagine the utility socket in your home. Each appliance in your home is different. So, every time you plug in an appliance to the socket the load added to the circuit is different. Whereas the circuit parameters such as wire resistance remain constant at normal temperature. The circuit needs to be analyzed each time a different appliance is plugged in. To avoid this problem, Léon Charles Thévenin came up with a new approach of circuit analysis, by which the fixed elements of the circuit can be replaced by their equivalent.

## Thevenin’s theorem

Thevenin’s theorem states that any linear network having a number of voltage sources and resistances can be replaced by a simple equivalent circuit consisting of a single voltage source (VTH)  in series with a resistance (RTH), where VTH is the open-circuit voltage at the terminals of the load and RTH is the equivalent resistance measured across the terminals while independent sources are turned off.

Simply, Thevenin’s theorem states that any linear network with several power sources, resistances and a variable load can be represented in a much simpler circuit containing a single voltage source (VTH)  in series with a resistance (RTH) and the variable load, where VTH is the open-circuit voltage at the terminals of the load and RTH is the equivalent resistance measured across the terminals while independent sources are turned off. See the below figure for better understanding.

## Solved examples

Thevenin’s theorem can be better understood from the below example:

Let’s find the Thevenin’s equivalent circuit for the above circuit.

In the above circuit, we have a voltage source (32V) and another current source (2A).

## Find Thevenin’s resistance

While calculating the equivalent resistance, all voltage sources must be turned off, meaning it acts like a short circuit and all current sources act like an open circuit, as shown in the figure below:

From the above circuit:

Thevenin’s resistance, Rth =  4 || 12 +1 = 4 x 12 / 16 + 1 = 4 ohms

## Find Thevenin’s voltage

Let’s do mesh analysis to find Thevenin’s voltage:

4i1 + 12(i1 – i2) = 32V, i2  = -2A

Solving the above equations, we get i1 = 0.5A

Therefore Vth = 12(i1 – i2) = 12(0.5 + 2) = 30V

The equivalent Thevenin’s circuit is shown in the figure below: